What does asterisk * mean in Python?

The Question :

327 people think this question is useful

Does * have a special meaning in Python as it does in C? I saw a function like this in the Python Cookbook:

def get(self, *a, **kw)

Would you please explain it to me or point out where I can find an answer (Google interprets the * as wild card character and thus I cannot find a satisfactory answer).

The Question Comments :
  • See also stackoverflow.com/questions/14301967/… for a bare asterisk
  • Is this still a duplicate? The referenced question is specifically about parameters to functions, while this question (at least from its title) would also cover syntax like [*my_dict]

The Answer 1

307 people think this answer is useful

See Function Definitions in the Language Reference.

If the form *identifier is present, it is initialized to a tuple receiving any excess positional parameters, defaulting to the empty tuple. If the form **identifier is present, it is initialized to a new dictionary receiving any excess keyword arguments, defaulting to a new empty dictionary.

Also, see Function Calls.

Assuming that one knows what positional and keyword arguments are, here are some examples:

Example 1:

# Excess keyword argument (python 2) example:
def foo(a, b, c, **args):
    print "a = %s" % (a,)
    print "b = %s" % (b,)
    print "c = %s" % (c,)
    print args

foo(a="testa", d="excess", c="testc", b="testb", k="another_excess")

As you can see in the above example, we only have parameters a, b, c in the signature of the foo function. Since d and k are not present, they are put into the args dictionary. The output of the program is:

a = testa
b = testb
c = testc
{'k': 'another_excess', 'd': 'excess'}

Example 2:

# Excess positional argument (python 2) example:
def foo(a, b, c, *args):
    print "a = %s" % (a,)
    print "b = %s" % (b,)
    print "c = %s" % (c,)
    print args

foo("testa", "testb", "testc", "excess", "another_excess")

Here, since we’re testing positional arguments, the excess ones have to be on the end, and *args packs them into a tuple, so the output of this program is:

a = testa
b = testb
c = testc
('excess', 'another_excess')

You can also unpack a dictionary or a tuple into arguments of a function:

def foo(a,b,c,**args):
    print "a=%s" % (a,)
    print "b=%s" % (b,)
    print "c=%s" % (c,)
    print "args=%s" % (args,)

argdict = dict(a="testa", b="testb", c="testc", excessarg="string")


args={'excessarg': 'string'}


def foo(a,b,c,*args):
    print "a=%s" % (a,)
    print "b=%s" % (b,)
    print "c=%s" % (c,)
    print "args=%s" % (args,)

argtuple = ("testa","testb","testc","excess")



The Answer 2

189 people think this answer is useful

I only have one thing to add that wasn’t clear from the other answers (for completeness’s sake).

You may also use the stars when calling the function. For example, say you have code like this:

>>> def foo(*args):
...     print(args)
>>> l = [1,2,3,4,5]

You can pass the list l into foo like so…

>>> foo(*l)
(1, 2, 3, 4, 5)

You can do the same for dictionaries…

>>> def foo(**argd):
...     print(argd)
>>> d = {'a' : 'b', 'c' : 'd'}
>>> foo(**d)
{'a': 'b', 'c': 'd'}

The Answer 3

82 people think this answer is useful

All of the above answers were perfectly clear and complete, but just for the record I’d like to confirm that the meaning of * and ** in python has absolutely no similarity with the meaning of similar-looking operators in C.

They are called the argument-unpacking and keyword-argument-unpacking operators.

The Answer 4

40 people think this answer is useful

A single star means that the variable ‘a’ will be a tuple of extra parameters that were supplied to the function. The double star means the variable ‘kw’ will be a variable-size dictionary of extra parameters that were supplied with keywords.

Although the actual behavior is spec’d out, it still sometimes can be very non-intuitive. Writing some sample functions and calling them with various parameter styles may help you understand what is allowed and what the results are.

def f0(a)
def f1(*a)
def f2(**a)
def f3(*a, **b)

The Answer 5

29 people think this answer is useful

I find * useful when writing a function that takes another callback function as a parameter:

def some_function(parm1, parm2, callback, *callback_args):
    a = 1
    b = 2
    callback(a, b, *callback_args)

That way, callers can pass in arbitrary extra parameters that will be passed through to their callback function. The nice thing is that the callback function can use normal function parameters. That is, it doesn’t need to use the * syntax at all. Here’s an example:

def my_callback_function(a, b, x, y, z):

x = 5
y = 6
z = 7

some_function('parm1', 'parm2', my_callback_function, x, y, z)

Of course, closures provide another way of doing the same thing without requiring you to pass x, y, and z through some_function() and into my_callback_function().


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