## The Question :

*411 people think this question is useful*

What is the most efficient way to map a function over a numpy array? The way I’ve been doing it in my current project is as follows:

import numpy as np
x = np.array([1, 2, 3, 4, 5])
# Obtain array of square of each element in x
squarer = lambda t: t ** 2
squares = np.array([squarer(xi) for xi in x])

However, this seems like it is probably very inefficient, since I am using a list comprehension to construct the new array as a Python list before converting it back to a numpy array.

Can we do better?

*The Question Comments :*

## The Answer 1

*341 people think this answer is useful*

I’ve tested all suggested methods plus `np.array(map(f, x))`

with `perfplot`

(a small project of mine).

Message #1: If you can use numpy’s native functions, do that.

If the function you’re trying to vectorize already *is* vectorized (like the `x**2`

example in the original post), using that is *much* faster than anything else (note the log scale):

If you actually need vectorization, it doesn’t really matter much which variant you use.

Code to reproduce the plots:

import numpy as np
import perfplot
import math
def f(x):
# return math.sqrt(x)
return np.sqrt(x)
vf = np.vectorize(f)
def array_for(x):
return np.array([f(xi) for xi in x])
def array_map(x):
return np.array(list(map(f, x)))
def fromiter(x):
return np.fromiter((f(xi) for xi in x), x.dtype)
def vectorize(x):
return np.vectorize(f)(x)
def vectorize_without_init(x):
return vf(x)
perfplot.show(
setup=lambda n: np.random.rand(n),
n_range=[2 ** k for k in range(20)],
kernels=[f, array_for, array_map, fromiter, vectorize, vectorize_without_init],
xlabel="len(x)",
)

## The Answer 2

*154 people think this answer is useful*

How about using `numpy.vectorize`

.

import numpy as np
x = np.array([1, 2, 3, 4, 5])
squarer = lambda t: t ** 2
vfunc = np.vectorize(squarer)
vfunc(x)
# Output : array([ 1, 4, 9, 16, 25])

## The Answer 3

*88 people think this answer is useful*

# TL;DR

As noted by @user2357112, a “direct” method of applying the function is always the fastest and simplest way to map a function over Numpy arrays:

import numpy as np
x = np.array([1, 2, 3, 4, 5])
f = lambda x: x ** 2
squares = f(x)

Generally avoid `np.vectorize`

, as it does not perform well, and has (or had) a number of issues. If you are handling other data types, you may want to investigate the other methods shown below.

# Comparison of methods

Here are some simple tests to compare three methods to map a function, this example using with Python 3.6 and NumPy 1.15.4. First, the set-up functions for testing:

import timeit
import numpy as np
f = lambda x: x ** 2
vf = np.vectorize(f)
def test_array(x, n):
t = timeit.timeit(
'np.array([f(xi) for xi in x])',
'from __main__ import np, x, f', number=n)
print('array: {0:.3f}'.format(t))
def test_fromiter(x, n):
t = timeit.timeit(
'np.fromiter((f(xi) for xi in x), x.dtype, count=len(x))',
'from __main__ import np, x, f', number=n)
print('fromiter: {0:.3f}'.format(t))
def test_direct(x, n):
t = timeit.timeit(
'f(x)',
'from __main__ import x, f', number=n)
print('direct: {0:.3f}'.format(t))
def test_vectorized(x, n):
t = timeit.timeit(
'vf(x)',
'from __main__ import x, vf', number=n)
print('vectorized: {0:.3f}'.format(t))

Testing with five elements (sorted from fastest to slowest):

x = np.array([1, 2, 3, 4, 5])
n = 100000
test_direct(x, n) # 0.265
test_fromiter(x, n) # 0.479
test_array(x, n) # 0.865
test_vectorized(x, n) # 2.906

With 100s of elements:

x = np.arange(100)
n = 10000
test_direct(x, n) # 0.030
test_array(x, n) # 0.501
test_vectorized(x, n) # 0.670
test_fromiter(x, n) # 0.883

And with 1000s of array elements or more:

x = np.arange(1000)
n = 1000
test_direct(x, n) # 0.007
test_fromiter(x, n) # 0.479
test_array(x, n) # 0.516
test_vectorized(x, n) # 0.945

Different versions of Python/NumPy and compiler optimization will have different results, so do a similar test for your environment.

## The Answer 4

*56 people think this answer is useful*

There are numexpr, numba and cython around, the goal of this answer is to take these possibilities into consideration.

But first let’s state the obvious: no matter how you map a Python-function onto a numpy-array, it stays a Python function, that means for every evaluation:

- numpy-array element must be converted to a Python-object (e.g. a
`Float`

).
- all calculations are done with Python-objects, which means to have the overhead of interpreter, dynamic dispatch and immutable objects.

So which machinery is used to actually loop through the array doesn’t play a big role because of the overhead mentioned above – it stays much slower than using numpy’s built-in functionality.

Let’s take a look at the following example:

# numpy-functionality
def f(x):
return x+2*x*x+4*x*x*x
# python-function as ufunc
import numpy as np
vf=np.vectorize(f)
vf.__name__="vf"

`np.vectorize`

is picked as a representative of the pure-python function class of approaches. Using `perfplot`

(see code in the appendix of this answer) we get the following running times:

We can see, that the numpy-approach is 10x-100x faster than the pure python version. The decrease of performance for bigger array-sizes is probably because data no longer fits the cache.

It is worth also mentioning, that `vectorize`

also uses a lot of memory, so often memory-usage is the bottle-neck (see related SO-question). Also note, that numpy’s documentation on `np.vectorize`

states that it is “provided primarily for convenience, not for performance”.

Other tools should be used, when performance is desired, beside writing a C-extension from the scratch, there are following possibilities:

One often hears, that the numpy-performance is as good as it gets, because it is pure C under the hood. Yet there is a lot room for improvement!

The vectorized numpy-version uses a lot of additional memory and memory-accesses. Numexp-library tries to tile the numpy-arrays and thus get a better cache utilization:

# less cache misses than numpy-functionality
import numexpr as ne
def ne_f(x):
return ne.evaluate("x+2*x*x+4*x*x*x")

Leads to the following comparison:

I cannot explain everything in the plot above: we can see bigger overhead for numexpr-library at the beginning, but because it utilize the cache better it is about 10 time faster for bigger arrays!

Another approach is to jit-compile the function and thus getting a real pure-C UFunc. This is numba’s approach:

# runtime generated C-function as ufunc
import numba as nb
@nb.vectorize(target="cpu")
def nb_vf(x):
return x+2*x*x+4*x*x*x

It is 10 times faster than the original numpy-approach:

However, the task is embarrassingly parallelizable, thus we also could use `prange`

in order to calculate the loop in parallel:

@nb.njit(parallel=True)
def nb_par_jitf(x):
y=np.empty(x.shape)
for i in nb.prange(len(x)):
y[i]=x[i]+2*x[i]*x[i]+4*x[i]*x[i]*x[i]
return y

As expected, the parallel function is slower for smaller inputs, but faster (almost factor 2) for larger sizes:

While numba specializes on optimizing operations with numpy-arrays, Cython is a more general tool. It is more complicated to extract the same performance as with numba – often it is down to llvm (numba) vs local compiler (gcc/MSVC):

%%cython -c=/openmp -a
import numpy as np
import cython
#single core:
@cython.boundscheck(False)
@cython.wraparound(False)
def cy_f(double[::1] x):
y_out=np.empty(len(x))
cdef Py_ssize_t i
cdef double[::1] y=y_out
for i in range(len(x)):
y[i] = x[i]+2*x[i]*x[i]+4*x[i]*x[i]*x[i]
return y_out
#parallel:
from cython.parallel import prange
@cython.boundscheck(False)
@cython.wraparound(False)
def cy_par_f(double[::1] x):
y_out=np.empty(len(x))
cdef double[::1] y=y_out
cdef Py_ssize_t i
cdef Py_ssize_t n = len(x)
for i in prange(n, nogil=True):
y[i] = x[i]+2*x[i]*x[i]+4*x[i]*x[i]*x[i]
return y_out

Cython results in somewhat slower functions:

# Conclusion

Obviously, testing only for one function doesn’t prove anything. Also one should keep in mind, that for the choosen function-example, the bandwidth of the memory was the bottle neck for sizes larger than 10^5 elements – thus we had the same performance for numba, numexpr and cython in this region.

In the end, the ultimative answer depends on the type of function, hardware, Python-distribution and other factors. For example Anaconda-distribution uses Intel’s VML for numpy’s functions and thus outperforms numba (unless it uses SVML, see this SO-post) easily for transcendental functions like `exp`

, `sin`

, `cos`

and similar – see e.g. the following SO-post.

Yet from this investigation and from my experience so far, I would state, that numba seems to be the easiest tool with best performance as long as no transcendental functions are involved.

Plotting running times with perfplot-package:

import perfplot
perfplot.show(
setup=lambda n: np.random.rand(n),
n_range=[2**k for k in range(0,24)],
kernels=[
f,
vf,
ne_f,
nb_vf, nb_par_jitf,
cy_f, cy_par_f,
],
logx=True,
logy=True,
xlabel='len(x)'
)

## The Answer 5

*36 people think this answer is useful*

squares = squarer(x)

Arithmetic operations on arrays are automatically applied elementwise, with efficient C-level loops that avoid all the interpreter overhead that would apply to a Python-level loop or comprehension.

Most of the functions you’d want to apply to a NumPy array elementwise will just work, though some may need changes. For example, `if`

doesn’t work elementwise. You’d want to convert those to use constructs like `numpy.where`

:

def using_if(x):
if x < 5:
return x
else:
return x**2

becomes

def using_where(x):
return numpy.where(x < 5, x, x**2)

## The Answer 6

*11 people think this answer is useful*

It seems no one has mentioned a built-in factory method of producing `ufunc`

in numpy package: `np.frompyfunc`

which I have tested again `np.vectorize`

and have outperformed it by about 20~30%. Of course it will perform well as prescribed C code or even `numba`

(which I have not tested), but it can a better alternative than `np.vectorize`

f = lambda x, y: x * y
f_arr = np.frompyfunc(f, 2, 1)
vf = np.vectorize(f)
arr = np.linspace(0, 1, 10000)
%timeit f_arr(arr, arr) # 307ms
%timeit vf(arr, arr) # 450ms

I have also tested larger samples, and the improvement is proportional. See the documentation also here

## The Answer 7

*10 people think this answer is useful*

**Edit:** *the original answer was misleading,* `np.sqrt`

*was applied directly to the array, just with a small overhead*.

In multidimensional cases where you want to apply a builtin function that operates on a 1d array, numpy.apply_along_axis is a good choice, also for more complex function compositions from numpy and scipy.

*Previous misleading statement:*

Adding the method:

def along_axis(x):
return np.apply_along_axis(f, 0, x)

to the perfplot code gives performance results close to `np.sqrt`

.

## The Answer 8

*9 people think this answer is useful*

I believe in newer version( I use 1.13) of numpy you can simply call the function by passing the numpy array to the fuction that you wrote for scalar type, it will automatically apply the function call to each element over the numpy array and return you another numpy array

>>> import numpy as np
>>> squarer = lambda t: t ** 2
>>> x = np.array([1, 2, 3, 4, 5])
>>> squarer(x)
array([ 1, 4, 9, 16, 25])

## The Answer 9

*2 people think this answer is useful*

As mentioned in this post, just use generator expressions like so:

numpy.fromiter((<some_func>(x) for x in <something>),<dtype>,<size of something>)

## The Answer 10

*2 people think this answer is useful*

All above answers compares well, but if you need to use custom function for mapping, and you have `numpy.ndarray`

, and you need to retain the shape of array.

I have compare just two, but it will retain the shape of `ndarray`

. I have used the array with 1 million entries for comparison. Here I use square function, which is also inbuilt in numpy and has great performance boost, since there as was need of something, you can use function of your choice.

import numpy, time
def timeit():
y = numpy.arange(1000000)
now = time.time()
numpy.array([x * x for x in y.reshape(-1)]).reshape(y.shape)
print(time.time() - now)
now = time.time()
numpy.fromiter((x * x for x in y.reshape(-1)), y.dtype).reshape(y.shape)
print(time.time() - now)
now = time.time()
numpy.square(y)
print(time.time() - now)

**Output**

>>> timeit()
1.162431240081787 # list comprehension and then building numpy array
1.0775556564331055 # from numpy.fromiter
0.002948284149169922 # using inbuilt function

here you can clearly see `numpy.fromiter`

works great considering to simple approach, and if inbuilt function is available please use that.

## The Answer 11

*0 people think this answer is useful*