# python – How do I resize an image using PIL and maintain its aspect ratio?

## The Question :

476 people think this question is useful

Is there an obvious way to do this that I’m missing? I’m just trying to make thumbnails.

The Question Comments :

## The Answer 1

511 people think this answer is useful

Define a maximum size. Then, compute a resize ratio by taking min(maxwidth/width, maxheight/height).

The proper size is oldsize*ratio.

There is of course also a library method to do this: the method Image.thumbnail.
Below is an (edited) example from the PIL documentation.

import os, sys
import Image

size = 128, 128

for infile in sys.argv[1:]:
outfile = os.path.splitext(infile)[0] + ".thumbnail"
if infile != outfile:
try:
im = Image.open(infile)
im.thumbnail(size, Image.ANTIALIAS)
im.save(outfile, "JPEG")
except IOError:
print "cannot create thumbnail for '%s'" % infile



## The Answer 2

282 people think this answer is useful

This script will resize an image (somepic.jpg) using PIL (Python Imaging Library) to a width of 300 pixels and a height proportional to the new width. It does this by determining what percentage 300 pixels is of the original width (img.size[0]) and then multiplying the original height (img.size[1]) by that percentage. Change “basewidth” to any other number to change the default width of your images.

from PIL import Image

basewidth = 300
img = Image.open('somepic.jpg')
wpercent = (basewidth/float(img.size[0]))
hsize = int((float(img.size[1])*float(wpercent)))
img = img.resize((basewidth,hsize), Image.ANTIALIAS)
img.save('somepic.jpg')



## The Answer 3

70 people think this answer is useful

I also recommend using PIL’s thumbnail method, because it removes all the ratio hassles from you.

One important hint, though: Replace

im.thumbnail(size)



with

im.thumbnail(size,Image.ANTIALIAS)



by default, PIL uses the Image.NEAREST filter for resizing which results in good performance, but poor quality.

## The Answer 4

49 people think this answer is useful

Based in @tomvon, I finished using the following (pick your case):

a) Resizing height (I know the new width, so I need the new height)

new_width  = 680
new_height = new_width * height / width



b) Resizing width (I know the new height, so I need the new width)

new_height = 680
new_width  = new_height * width / height



Then just:

img = img.resize((new_width, new_height), Image.ANTIALIAS)



## The Answer 5

18 people think this answer is useful

If you are trying to maintain the same aspect ratio, then wouldn’t you resize by some percentage of the original size?

For example, half the original size

half = 0.5
out = im.resize( [int(half * s) for s in im.size] )



## The Answer 6

15 people think this answer is useful

PIL already has the option to crop an image

img = ImageOps.fit(img, size, Image.ANTIALIAS)



## The Answer 7

15 people think this answer is useful
from PIL import Image

img = Image.open('/your image path/image.jpg') # image extension *.png,*.jpg
new_width  = 200
new_height = 300
img = img.resize((new_width, new_height), Image.ANTIALIAS)
img.save('output image name.png') # format may what you want *.png, *jpg, *.gif



## The Answer 8

7 people think this answer is useful
from PIL import Image
from resizeimage import resizeimage

def resize_file(in_file, out_file, size):
with open(in_file) as fd:
image = resizeimage.resize_thumbnail(Image.open(fd), size)
image.save(out_file)
image.close()

resize_file('foo.tif', 'foo_small.jpg', (256, 256))



I use this library:

pip install python-resize-image



## The Answer 9

7 people think this answer is useful

If you don’t want / don’t have a need to open image with Pillow, use this:

from PIL import Image

new_img_arr = numpy.array(Image.fromarray(img_arr).resize((new_width, new_height), Image.ANTIALIAS))



## The Answer 10

4 people think this answer is useful

Just updating this question with a more modern wrapper This library wraps Pillow (a fork of PIL) https://pypi.org/project/python-resize-image/

Allowing you to do something like this :-

from PIL import Image
from resizeimage import resizeimage

fd_img = open('test-image.jpeg', 'r')
img = Image.open(fd_img)
img = resizeimage.resize_width(img, 200)
img.save('test-image-width.jpeg', img.format)
fd_img.close()



Heaps more examples in the above link.

## The Answer 11

4 people think this answer is useful

I was trying to resize some images for a slideshow video and because of that, I wanted not just one max dimension, but a max width and a max height (the size of the video frame).
And there was always the possibility of a portrait video…
The Image.thumbnail method was promising, but I could not make it upscale a smaller image.

So after I couldn’t find an obvious way to do that here (or at some other places), I wrote this function and put it here for the ones to come:

from PIL import Image

def get_resized_img(img_path, video_size):
img = Image.open(img_path)
width, height = video_size  # these are the MAX dimensions
video_ratio = width / height
img_ratio = img.size[0] / img.size[1]
if video_ratio >= 1:  # the video is wide
if img_ratio <= video_ratio:  # image is not wide enough
width_new = int(height * img_ratio)
size_new = width_new, height
else:  # image is wider than video
height_new = int(width / img_ratio)
size_new = width, height_new
else:  # the video is tall
if img_ratio >= video_ratio:  # image is not tall enough
height_new = int(width / img_ratio)
size_new = width, height_new
else:  # image is taller than video
width_new = int(height * img_ratio)
size_new = width_new, height
return img.resize(size_new, resample=Image.LANCZOS)



## The Answer 12

4 people think this answer is useful

I will also add a version of the resize that keeps the aspect ratio fixed. In this case, it will adjust the height to match the width of the new image, based on the initial aspect ratio, asp_rat, which is float (!). But, to adjust the width to the height, instead, you just need to comment one line and uncomment the other in the else loop. You will see, where.

You do not need the semicolons (;), I keep them just to remind myself of syntax of languages I use more often.

from PIL import Image

img_path = "filename.png";
img = Image.open(img_path);     # puts our image to the buffer of the PIL.Image object

width, height = img.size;
asp_rat = width/height;

# Enter new width (in pixels)
new_width = 50;

# Enter new height (in pixels)
new_height = 54;

new_rat = new_width/new_height;

if (new_rat == asp_rat):
img = img.resize((new_width, new_height), Image.ANTIALIAS);

# adjusts the height to match the width
# NOTE: if you want to adjust the width to the height, instead ->
# uncomment the second line (new_width) and comment the first one (new_height)
else:
new_height = round(new_width / asp_rat);
#new_width = round(new_height * asp_rat);
img = img.resize((new_width, new_height), Image.ANTIALIAS);

# usage: resize((x,y), resample)
# resample filter -> PIL.Image.BILINEAR, PIL.Image.NEAREST (default), PIL.Image.BICUBIC, etc..

# Enter the name under which you would like to save the new image
img.save("outputname.png");



And, it is done. I tried to document it as much as I can, so it is clear.

I hope it might be helpful to someone out there!

## The Answer 13

3 people think this answer is useful

A simple method for keeping constrained ratios and passing a max width / height. Not the prettiest but gets the job done and is easy to understand:

def resize(img_path, max_px_size, output_folder):
with Image.open(img_path) as img:
width_0, height_0 = img.size
out_f_name = os.path.split(img_path)[-1]
out_f_path = os.path.join(output_folder, out_f_name)

if max((width_0, height_0)) <= max_px_size:
print('writing {} to disk (no change from original)'.format(out_f_path))
img.save(out_f_path)
return

if width_0 > height_0:
wpercent = max_px_size / float(width_0)
hsize = int(float(height_0) * float(wpercent))
img = img.resize((max_px_size, hsize), Image.ANTIALIAS)
print('writing {} to disk'.format(out_f_path))
img.save(out_f_path)
return

if width_0 < height_0:
hpercent = max_px_size / float(height_0)
wsize = int(float(width_0) * float(hpercent))
img = img.resize((max_px_size, wsize), Image.ANTIALIAS)
print('writing {} to disk'.format(out_f_path))
img.save(out_f_path)
return



Here’s a python script that uses this function to run batch image resizing.

## The Answer 14

3 people think this answer is useful

Have updated the answer above by “tomvon”

from PIL import Image

img = Image.open(image_path)

width, height = img.size[:2]

if height > width:
baseheight = 64
hpercent = (baseheight/float(img.size[1]))
wsize = int((float(img.size[0])*float(hpercent)))
img = img.resize((wsize, baseheight), Image.ANTIALIAS)
img.save('resized.jpg')
else:
basewidth = 64
wpercent = (basewidth/float(img.size[0]))
hsize = int((float(img.size[1])*float(wpercent)))
img = img.resize((basewidth,hsize), Image.ANTIALIAS)
img.save('resized.jpg')



## The Answer 15

2 people think this answer is useful

My ugly example.

Function get file like: “pic[0-9a-z].[extension]”, resize them to 120×120, moves section to center and save to “ico[0-9a-z].[extension]”, works with portrait and landscape:

def imageResize(filepath):
from PIL import Image
file_dir=os.path.split(filepath)
img = Image.open(filepath)

if img.size[0] > img.size[1]:
aspect = img.size[1]/120
new_size = (img.size[0]/aspect, 120)
else:
aspect = img.size[0]/120
new_size = (120, img.size[1]/aspect)
img.resize(new_size).save(file_dir[0]+'/ico'+file_dir[1][3:])
img = Image.open(file_dir[0]+'/ico'+file_dir[1][3:])

if img.size[0] > img.size[1]:
new_img = img.crop( (
(((img.size[0])-120)/2),
0,
120+(((img.size[0])-120)/2),
120
) )
else:
new_img = img.crop( (
0,
(((img.size[1])-120)/2),
120,
120+(((img.size[1])-120)/2)
) )

new_img.save(file_dir[0]+'/ico'+file_dir[1][3:])



## The Answer 16

2 people think this answer is useful

I resizeed the image in such a way and it’s working very well

from io import BytesIO
import os, sys
from PIL import Image

def imageResize(image):
outputIoStream = BytesIO()
imageTemproaryResized = imageTemproary.resize( (1920,1080), Image.ANTIALIAS)
imageTemproaryResized.save(outputIoStream , format='PNG', quality='10')
outputIoStream.seek(0)
uploadedImage = InMemoryUploadedFile(outputIoStream,'ImageField', "%s.jpg" % image.name.split('.')[0], 'image/jpeg', sys.getsizeof(outputIoStream), None)

## For upload local folder
fs = FileSystemStorage()



## The Answer 17

2 people think this answer is useful

Open your image file

from PIL import Image
im = Image.open("image.png")



Use PIL Image.resize(size, resample=0) method, where you substitute (width, height) of your image for the size 2-tuple.

This will display your image at original size:

display(im.resize((int(im.size[0]),int(im.size[1])), 0) )



This will display your image at 1/2 the size:

display(im.resize((int(im.size[0]/2),int(im.size[1]/2)), 0) )



This will display your image at 1/3 the size:

display(im.resize((int(im.size[0]/3),int(im.size[1]/3)), 0) )



This will display your image at 1/4 the size:

display(im.resize((int(im.size[0]/4),int(im.size[1]/4)), 0) )



etc etc

## The Answer 18

0 people think this answer is useful

The following script creates nice thumbnails of all JPEG images preserving aspect ratios with 128×128 max resolution.

from PIL import Image
img = Image.open("D:\\Pictures\\John.jpg")
img.thumbnail((680,680))
img.save("D:\\Pictures\\John_resize.jpg")



## The Answer 19

-1 people think this answer is useful
import cv2
from skimage import data
import matplotlib.pyplot as plt
from skimage.util import img_as_ubyte
from skimage import io
filename='abc.png'
print(im.shape)
im.resize(300,300)
print(im.shape)
plt.imshow(image)



## The Answer 20

-2 people think this answer is useful

You can resize image by below code:

From PIL import Image
img=Image.open('Filename.jpg') # paste image in python folder
print(img.size())
new_img=img.resize((400,400))
new_img.save('new_filename.jpg')