# How to split a string into an array of characters in Python?

## The Question :

494 people think this question is useful

I’ve tried to look around the web for answers to splitting a string into an array of characters but I can’t seem to find a simple method

str.split(//) does not seem to work like Ruby does. Is there a simple way of doing this without looping?

The Question Comments :
• In Python, strings are already arrays of characters for all purposes except replacement. You can slice them, reference or look up items by index, etc.
• Link to other direction

## The Answer 1

929 people think this answer is useful
>>> s = "foobar"
>>> list(s)
['f', 'o', 'o', 'b', 'a', 'r']



You need list

## The Answer 2

78 people think this answer is useful

You take the string and pass it to list()

s = "mystring"
l = list(s)
print l



## The Answer 3

66 people think this answer is useful

You can also do it in this very simple way without list():

>>>
['f', 'o', 'o', 'b', 'a', 'r']



## The Answer 4

49 people think this answer is useful

If you want to process your String one character at a time. you have various options.

uhello = u'Hello\u0020World'



Using List comprehension:

print([x for x in uhello])



Output:

['H', 'e', 'l', 'l', 'o', ' ', 'W', 'o', 'r', 'l', 'd']



Using map:

print(list(map(lambda c2: c2, uhello)))



Output:

['H', 'e', 'l', 'l', 'o', ' ', 'W', 'o', 'r', 'l', 'd']



Calling Built in list function:

print(list(uhello))



Output:

['H', 'e', 'l', 'l', 'o', ' ', 'W', 'o', 'r', 'l', 'd']



Using for loop:

for c in uhello:
print(c)



Output:

H
e
l
l
o

W
o
r
l
d



## The Answer 5

21 people think this answer is useful

I explored another two ways to accomplish this task. It may be helpful for someone.

The first one is easy:

In [25]: a = []
In [26]: s = 'foobar'
In [27]: a += s
In [28]: a
Out[28]: ['f', 'o', 'o', 'b', 'a', 'r']



And the second one use map and lambda function. It may be appropriate for more complex tasks:

In [36]: s = 'foobar12'
In [37]: a = map(lambda c: c, s)
In [38]: a
Out[38]: ['f', 'o', 'o', 'b', 'a', 'r', '1', '2']



For example

# isdigit, isspace or another facilities such as regexp may be used
In [40]: a = map(lambda c: c if c.isalpha() else '', s)
In [41]: a
Out[41]: ['f', 'o', 'o', 'b', 'a', 'r', '', '']



See python docs for more methods

## The Answer 6

21 people think this answer is useful

I you just need an array of chars:

arr = list(str)



If you want to split the str by a particular str:

# str = "temp//temps" will will be ['temp', 'temps']
arr = str.split("//")



## The Answer 7

19 people think this answer is useful

The task boils down to iterating over characters of the string and collecting them into a list. The most naïve solution would look like

result = []
for character in string:
result.append(character)



Of course, it can be shortened to just

result = [character for character in string]



but there still are shorter solutions that do the same thing.

list constructor can be used to convert any iterable (iterators, lists, tuples, string etc.) to list.

>>> list('abc')
['a', 'b', 'c']



The big plus is that it works the same in both Python 2 and Python 3.

Also, starting from Python 3.5 (thanks to the awesome PEP 448) it’s now possible to build a list from any iterable by unpacking it to an empty list literal:

>>> [*'abc']
['a', 'b', 'c']



This is neater, and in some cases more efficient than calling list constructor directly.

I’d advise against using map-based approaches, because map does not return a list in Python 3. See How to use filter, map, and reduce in Python 3.

## The Answer 8

13 people think this answer is useful

split() inbuilt function will only separate the value on the basis of certain condition but in the single word, it cannot fulfill the condition. So, it can be solved with the help of list(). It internally calls the Array and it will store the value on the basis of an array.

Suppose,

a = "bottle"
a.split() // will only return the word but not split the every single char.

a = "bottle"
list(a) // will separate ['b','o','t','t','l','e']



## The Answer 9

10 people think this answer is useful

Unpack them:

word = "Paralelepipedo"
print([*word])



## The Answer 10

3 people think this answer is useful

If you wish to read only access to the string you can use array notation directly.

Python 2.7.6 (default, Mar 22 2014, 22:59:38)
[GCC 4.8.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> t = 'my string'
>>> t[1]
'y'



Could be useful for testing without using regexp. Does the string contain an ending newline?

>>> t[-1] == '\n'
False
>>> t = 'my string\n'
>>> t[-1] == '\n'
True



## The Answer 11

3 people think this answer is useful

You can use extend method in list operations as well.

>>> list1 = []
>>> list1.extend('somestring')
>>> list1
['s', 'o', 'm', 'e', 's', 't', 'r', 'i', 'n', 'g']



## The Answer 12

1 people think this answer is useful

Well, much as I like the list(s) version, here’s another more verbose way I found (but it’s cool so I thought I’d add it to the fray):

>>> text = "My hovercraft is full of eels"
>>>  for i in range(len(text))]
['M', 'y', ' ', 'h', 'o', 'v', 'e', 'r', 'c', 'r', 'a', 'f', 't', ' ', 'i', 's', ' ', 'f', 'u', 'l', 'l', ' ', 'o', 'f', ' ', 'e', 'e', 'l', 's']



## The Answer 13

1 people think this answer is useful
from itertools import chain

string = 'your string'
chain(string)



similar to list(string) but returns a generator that is lazily evaluated at point of use, so memory efficient.

## The Answer 14

-1 people think this answer is useful

To split a string s, the easiest way is to pass it to list(). So,

s = 'abc'
s_l = list(s) #  s_l is now ['a', 'b', 'c']



You can also use a list comprehension, which works but is not as concise as the above:

s_l =



There are other ways, as well, but these should suffice. Later, if you want to recombine them, a simple call to "".join(s_l) will return your list to all its former glory as a string…