# Delete first character of a string in Javascript

## The Question :

584 people think this question is useful

I want to delete the first character of a string, if the first character is a 0. The 0 can be there more than once.

Is there a simple function that checks the first character and deletes it if it is 0?

Right now, I’m trying it with the JS slice() function but it is very awkward.

922 people think this answer is useful

You can remove the first character of a string using substring:

var s1 = "foobar";
var s2 = s1.substring(1);



To remove all 0’s at the start of the string:

var s = "0000test";
while(s.charAt(0) === '0')
{
s = s.substring(1);
}



203 people think this answer is useful

Very readable code is to use .substring() with a start set to index of the second character (1) (first character has index 0). Second parameter of the .substring() method is actually optional, so you don’t even need to call .length()

# TL;DR : Remove first character from the string:

str = str.substring(1);



…yes it is that simple…

## Removing some particular character(s):

As @Shaded suggested, just loop this while first character of your string is the “unwanted” character…

var yourString = "0000test";
var unwantedCharacter = "0";
//there is really no need for === check, since we use String's charAt()
while( yourString.charAt(0) == unwantedCharacter ) yourString = yourString.substring(1);
//yourString now contains "test"



## .slice() vs .substring() vs .substr()

EDIT: substr() is not standardized and should not be used for new JS codes, you may be inclined to use it because of the naming similarity with other languages, e.g. PHP, but even in PHP you should probably use mb_substr() to be safe in modern world 🙂

Quote from (and more on that in) What is the difference between String.slice and String.substring?

He also points out that if the parameters to slice are negative, they reference the string from the end. Substring and substr doesn´t.

88 people think this answer is useful

Example: http://jsfiddle.net/kCpNQ/

var myString = "0String";

if( myString.charAt( 0 ) === '0' )
myString = myString.slice( 1 );



If there could be several 0 characters at the beginning, you can change the if() to a while().

Example: http://jsfiddle.net/kCpNQ/1/

var myString = "0000String";

while( myString.charAt( 0 ) === '0' )
myString = myString.slice( 1 );



64 people think this answer is useful

The easiest way to strip all leading 0s is:

var s = "00test";
s = s.replace(/^0+/, "");



If just stripping a single leading 0 character, as the question implies, you could use

s = s.replace(/^0/, "");



27 people think this answer is useful

You can do it with substring method:

let a = "My test string";

a = a.substring(1);

console.log(a); // y test string



18 people think this answer is useful

Did you try the substring function?

string = string.indexOf(0) == '0' ? string.substring(1) : string;



And you can always do this for multiple 0s:

while(string.indexOf(0) == '0')
{
string = string.substring(1);
}



7 people think this answer is useful
var s = "0test";
if(s.substr(0,1) == "0") {
s = s.substr(1);
}



For all 0s: http://jsfiddle.net/An4MY/

String.prototype.ltrim0 = function() {
return this.replace(/^[0]+/,"");
}
var s = "0000test".ltrim0();



6 people think this answer is useful
//---- remove first and last char of str
str = str.substring(1,((keyw.length)-1));

//---- remove only first char
str = str.substring(1,(keyw.length));

//---- remove only last char
str = str.substring(0,(keyw.length));



3 people think this answer is useful

Here’s one that doesn’t assume the input is a string, uses substring, and comes with a couple of unit tests:

var cutOutZero = function(value) {
if (value.length &amp;&amp; value.length > 0 &amp;&amp; value[0] === '0') {
return value.substring(1);
}

return value;
};



http://jsfiddle.net/TRU66/1/

3 people think this answer is useful

String.prototype.trimStartWhile = function(predicate) {
if (typeof predicate !== "function") {
return this;
}
let len = this.length;
if (len === 0) {
return this;
}
let s = this, i = 0;
while (i < len &amp;&amp; predicate(s[i])) {
i++;
}
return s.substr(i)
}

let str = "0000000000ABC",
r = str.trimStartWhile(c => c === '0');

console.log(r);


2 people think this answer is useful

try

s.replace(/^0/,'')



console.log("0string  =>", "0string".replace(/^0/,'') );
console.log("00string =>", "00string".replace(/^0/,'') );
console.log("string00 =>", "string00".replace(/^0/,'') );


0 people think this answer is useful
var test = '0test';
test = test.replace(/0(.*)/, '$1');  ## The Answer 13 0 people think this answer is useful From the Javascript implementation of trim() > that removes and leading or ending spaces from strings. Here is an altered implementation of the answer for this question. var str = "0000one two three0000"; //TEST str = str.replace(/^\s+|\s+$/g,'0'); //ANSWER



Original implementation for this on JS

string.trim():
if (!String.prototype.trim) {
String.prototype.trim = function() {
return this.replace(/^\s+|\s+\$/g,'');
}
}



0 people think this answer is useful

Another alternative to get the first character after deleting it:

// Example string
let string = 'Example';

// Getting the first character and updtated string
[character, string] = [string[0], string.substr(1)];

console.log(character);
// 'E'

console.log(string);
// 'xample'