javascript – indexOf method in an object array?

The Question :

572 people think this question is useful

What’s the best method to get the index of an array which contains objects?

Imagine this scenario:

var hello = {
    hello: 'world',
    foo: 'bar'
};
var qaz = {
    hello: 'stevie',
    foo: 'baz'
}

var myArray = [];
myArray.push(hello,qaz);

Now I would like to have the indexOf the object which hello property is 'stevie' which, in this example, would be 1.

I’m pretty newbie with JavaScript and I don’t know if there is a simple method or if I should build my own function to do that.

The Question Comments :
  • Do you want to merge the two objects hello and qaz?
  • Nope I don’t. I want to have a list of objects in an array.
  • Ah okay! You want to know the position of the whole object in the array, which has a defined property.
  • I found a very simple function to solve this exact problem with this SO answer: var elementPos = array.map(function(x) {return x.id; }).indexOf(idYourAreLookingFor); var objectFound = array[elementPos]; [link] (stackoverflow.com/a/16100446/1937255)
  • ES6 Array.indexOf is better than accepted answer (if ES6 works for you) – see full example below

The Answer 1

1137 people think this answer is useful

I think you can solve it in one line using the map function:

pos = myArray.map(function(e) { return e.hello; }).indexOf('stevie');

The Answer 2

410 people think this answer is useful

Array.prototype.findIndex is supported in all browsers other than IE (non-edge). But the polyfill provided is nice.

var indexOfStevie = myArray.findIndex(i => i.hello === "stevie");

The solution with map is okay. But you are iterating over the entire array every search. That is only the worst case for findIndex which stops iterating once a match is found.


There’s not really a concise way (when devs had to worry about IE8), but here’s a common solution:
var searchTerm = "stevie",
    index = -1;
for(var i = 0, len = myArray.length; i < len; i++) {
    if (myArray[i].hello === searchTerm) {
        index = i;
        break;
    }
}

or as a function:

function arrayObjectIndexOf(myArray, searchTerm, property) {
    for(var i = 0, len = myArray.length; i < len; i++) {
        if (myArray[i][property] === searchTerm) return i;
    }
    return -1;
}
arrayObjectIndexOf(arr, "stevie", "hello"); // 1

Just some notes:

  1. Don’t use for…in loops on arrays
  2. Be sure to break out of the loop or return out of the function once you’ve found your “needle”
  3. Be careful with object equality

For example,

var a = {obj: 0};
var b = [a];
b.indexOf({obj: 0}); // -1 not found

The Answer 3

134 people think this answer is useful

In ES2015, this is pretty easy:

myArray.map(x => x.hello).indexOf('stevie')

or, probably with better performance for larger arrays:

myArray.findIndex(x => x.hello === 'stevie')

The Answer 4

24 people think this answer is useful
var idx = myArray.reduce( function( cur, val, index ){

    if( val.hello === "stevie" &amp;&amp; cur === -1 ) {
        return index;
    }
    return cur;

}, -1 );

The Answer 5

17 people think this answer is useful

I like Pablo’s answer, but Array#indexOf and Array#map don’t work on all browsers. Underscore will use native code if it’s available, but has fallbacks as well. Plus it has the pluck method for doing exactly what Pablo’s anonymous map method does.

var idx = _.chain(myArray).pluck("hello").indexOf("Stevie").value();

The Answer 6

14 people think this answer is useful

Or prototype it :

Array.prototype.indexOfObject = function arrayObjectIndexOf(property, value) {
    for (var i = 0, len = this.length; i < len; i++) {
        if (this[i][property] === value) return i;
    }
    return -1;
}

myArr.indexOfObject("name", "stevie");

The Answer 7

8 people think this answer is useful

Brief

myArray.indexOf('stevie','hello')

Use Cases :

  /*****NORMAL****/  
[2,4,5].indexOf(4) ;//OUTPUT 1
 /****COMPLEX*****/
 [{slm:2},{slm:4},{slm:5}].indexOf(4,'slm');//OUTPUT 1
 //OR
 [{slm:2},{slm:4},{slm:5}].indexOf(4,function(e,i){
   return e.slm;
});//OUTPUT 1
/***MORE Complex**/
[{slm:{salat:2}},{slm:{salat:4}},{slm:{salat:5}}].indexOf(4,function(e,i){
   return e.slm.salat;
});//OUTPUT 1

API :

    Array.prototype.indexOfOld=Array.prototype.indexOf

    Array.prototype.indexOf=function(e,fn){
      if(!fn){return this.indexOfOld(e)}
      else{ 
       if(typeof fn ==='string'){var att=fn;fn=function(e){return e[att];}}
        return this.map(fn).indexOfOld(e);
      }
    };

The Answer 8

6 people think this answer is useful

I did some performance testing of various answers here, which anyone can run them self:

https://jsperf.com/find-index-of-object-in-array-by-contents

Based on my initial tests in Chrome, the following method (using a for loop set up inside a prototype) is the fastest:

Array.prototype.indexOfObject = function (property, value) {
    for (var i = 0, len = this.length; i < len; i++) {
        if (this[i][property] === value) return i;
    }
    return -1;
}

myArray.indexOfObject("hello", "stevie");

This code is a slightly modified version of Nathan Zaetta’s answer.

In the performance benchmarks I tried it with both the target being in the middle (index 500) and very end (index 999) of a 1000 object array, and even if I put the target in as the very last item in the array (meaning that it it has to loop through every single item in the array before it’s found) it still ends up the fastest.

This solution also has the benefit of being one of the most terse for repeatedly executing, since only the last line needs to be repeated:

myArray.indexOfObject("hello", "stevie");

The Answer 9

6 people think this answer is useful

I compared several methods and received a result with the fastest way to solve this problem. It’s a for loop. It’s 5+ times faster than any other method.

Here is the test’s page: https://jsbench.me/9hjewv6a98

The Answer 10

6 people think this answer is useful

While, most other answers here are valid. Sometimes, it’s best to just make a short simple function near where you will use it.

// indexOf wrapper for the list of objects
function indexOfbyKey(obj_list, key, value) {
    for (index in obj_list) {
        if (obj_list[index][key] === value) return index;
    }
    return -1;
}
// Find the string in the list (default -1)
var test1 = indexOfbyKey(object_list, 'name', 'Stevie');
var test2 = indexOfbyKey(object_list, 'last_name', 'some other name');

It depends on what is important to you. It might save lines of code and be very clever to use a one-liner, or to put a generic solution somewhere that covers various edge cases. But sometimes it’s better to just say: “here I did it like this” rather than leave future developers to have extra reverse engineering work. Especially if you consider yourself “a newbie” like in your question.

The Answer 11

5 people think this answer is useful

If your object is the same object of the ones you are using within the array, you should be able to get the index of the Object in the same way you do as if it was a string.

var hello = {
    hello: 'world',
    foo: 'bar'
};
var qaz = {
    hello: 'stevie',
    foo: 'baz'
}

var qazCLONE = { // new object instance and same structure
    hello: 'stevie',
    foo: 'baz'
}

var myArray = [hello,qaz];

myArray.indexOf(qaz) // should return 1
myArray.indexOf(qazCLONE) // should return -1

The Answer 12

4 people think this answer is useful
array.filter(function(item, indx, arr){ return(item.hello === 'stevie'); })[0];

Mind the [0].

It is proper to use reduce as in Antonio Laguna‘s answer.

Apologies for the brevity…

The Answer 13

3 people think this answer is useful

Try this:

console.log(Object.keys({foo:"_0_", bar:"_1_"}).indexOf("bar"));

https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Object/keys

The Answer 14

3 people think this answer is useful

simple:

myArray.indexOf(myArray.filter(function(item) {
    return item.hello == "stevie"
})[0])

The Answer 15

3 people think this answer is useful

If you are only interested into finding the position see @Pablo’s answer.

pos = myArray.map(function(e) { return e.hello; }).indexOf('stevie');

However, if you are looking forward to finding the element (i.e. if you were thinking of doing something like this myArray[pos]), there is a more efficient one-line way to do it, using filter.

element = myArray.filter((e) => e.hello === 'stevie')[0];

See perfomance results (~ +42% ops/sec): http://jsbench.github.io/#7fa01f89a5dc5cc3bee79abfde80cdb3

The Answer 16

2 people think this answer is useful

See this example: http://jsfiddle.net/89C54/

for (i = 0; i < myArray.length; i++) {
    if (myArray[i].hello === 'stevie') {
        alert('position: ' + i);
        return;
    }
}

It starts to count with zero.

The Answer 17

2 people think this answer is useful

I have made a generic function to check the below is the code & works for any object

function indexOfExt(list, item) {
    var len = list.length;

    for (var i = 0; i < len; i++) {
        var keys = Object.keys(list[i]);
        var flg = true;
        for (var j = 0; j < keys.length; j++) {
            var value = list[i][keys[j]];
            if (item[keys[j]] !== value) {
                flg = false;
            }
        }
        if (flg == true) {
            return i;
        }
    }
    return -1;
}

var items = [{ "hello": 'world', "foo": 'bar' }];
var selectedItem = { "hello": 'world', "foo": 'bar' };
alert(items.indexOf(selectedItem));
alert(indexOfExt(items, selectedItem));

The first alert will return -1 (means match not found) & second alert will return 0 (means match found).

The Answer 18

2 people think this answer is useful

Use _.findIndex from underscore.js library

Here’s the example _.findIndex([{a:1},{a: 2,c:10},{a: 3}], {a:2,c:10}) //1

The Answer 19

2 people think this answer is useful

Using the ES6 findIndex method, without lodash or any other libraries, you can write:

function deepIndexOf(arr, obj) {
  return arr.findIndex(function (cur) {
    return Object.keys(obj).every(function (key) {
      return obj[key] === cur[key];
    });
  });
}

This will compare the immediate properties of the object, but not recurse into the properties.

If your implementation doesn’t provide findIndex yet (most don’t), you can add a light polyfill that supports this search:

function deepIndexOf(arr, obj) {
  function findIndex = Array.prototype.findIndex || function (pred) {
    for (let i = 0; i < this.length; ++i) {
      if (pred.call(this, this[i], i)) {
        return i;
      }
    }

    return -1;
  }

  return findIndex.call(arr, function (cur) {
    return Object.keys(obj).every(function (key) {
      return obj[key] === cur[key];
    });
  });
}

(from my answer on this dupe)

The Answer 20

2 people think this answer is useful

You can use a native and convenient function Array.prototype.findIndex() basically:

The findIndex() method returns an index in the array, if an element in the array satisfies the provided testing function. Otherwise -1 is returned.

Just a note it is not supported on Internet Explorer, Opera and Safari, but you can use a Polyfill provided in the link below.

More information:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/findIndex

var hello = {
  hello: 'world',
  foo: 'bar'
};
var qaz = {
  hello: 'stevie',
  foo: 'baz'
}

var myArray = [];
myArray.push(hello, qaz);

var index = myArray.findIndex(function(element, index, array) {
  if (element.hello === 'stevie') {
    return true;
  }
});
alert('stevie is at index: ' + index);

The Answer 21

2 people think this answer is useful

Furthor of @Monika Garg answer, you can use findIndex() (There is a polyfill for unsupprted browsers).

I saw that people downvoted this answer, and I hope that they did this because of the wrong syntax, because on my opinion, this is the most elegant way.

The findIndex() method returns an index in the array, if an element in the array satisfies the provided testing function. Otherwise -1 is returned.

For example:

var hello = {
  hello: 'world',
  foo: 'bar'
};
var qaz = {
  hello: 'stevie',
  foo: 'baz'
}

var myArray = [];
myArray.push(hello,qaz);

var index = myArray.findIndex(function(element) {
  return element.hello == 'stevie';
});

alert(index);

The Answer 22

1 people think this answer is useful

This is the way to find the object’s index in array

    var myArray = [{  hello: 'world',
        foo: 'bar'
    },{
        hello: 'stevie',
        foo: 'baz'
    }];



    for (i = 0; i < myArray.length; i++) {
        if (myArray[i].hello === 'stevie') {
            alert('position: ' + i);
            return;
        }
    }

The Answer 23

0 people think this answer is useful

This works without custom code

var arr, a, found;
arr = [{x: 1, y: 2}];
a = {x: 1, y: 2};
found = JSON.stringify(arr).indexOf(JSON.stringify(a)) > - 1;
// found === true

Note: this does not give the actual index, it only tells if your object exists in the current data structure

The Answer 24

0 people think this answer is useful

You can simply use

const someId = 2;
const array = [{id:1}, {id:2}, {id:3}];
const index = array.reduce((i, item, index) => item.id === someId ? index : i, -1);
alert('someId ' + someId + ' is at index ' + index);

No underscore, no for, just a reduce.

The Answer 25

0 people think this answer is useful
var hello = {hello: "world",  foo: "bar"};
var qaz = {hello: "stevie", foo: "baz"};
var myArray = [];
myArray.push(hello,qaz);

function indexOfObject( arr, key, value   ) {
    var j = -1;
    var result = arr.some(function(obj, i) { 
        j++;
        return obj[key] == value;
    })

    if (!result) {
        return -1;
    } else {
        return j;
    };
}

alert(indexOfObject(myArray,"hello","world"));

The Answer 26

-1 people think this answer is useful

You can create your own prototype to do this:

something like:

Array.prototype.indexOfObject = function (object) {
    for (var i = 0; i < this.length; i++) {
        if (JSON.stringify(this[i]) === JSON.stringify(object))
            return i;
    }
}

The Answer 27

-2 people think this answer is useful

I will prefer to use findIndex() method:

 var index = myArray.findIndex('hello','stevie');

index will give you the index number.

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