sql – Convert timestamp to date in MySQL query

The Question :

210 people think this question is useful

I want to convert a timestamp in MySQL to a date.

I would like to format the user.registration field into the text file as a yyyy-mm-dd.

Here is my SQL:

$sql = requestSQL("SELECT user.email, 
                   info.name, 
                   FROM_UNIXTIME(user.registration),
                   info.news
                   FROM user, info 
                   WHERE user.id = info.id ", "export members");

I also tried the date conversion with:

DATE_FORMAT(user.registration, '%d/%m/%Y')
DATE(user.registration)

I echo the result before to write the text file and I get :

email1;name1;DATE_FORMAT(user.registration, ‘%d/%m/%Y’);news1

email2;name2;news2

How can I convert that field to date?

The Question Comments :
  • Its saving the file exactly like that? What is the code you’re using to run the sql query?
  • I edited my question, requeteSQL is running the query

The Answer 1

399 people think this answer is useful
DATE_FORMAT(FROM_UNIXTIME(`user.registration`), '%e %b %Y') AS 'date_formatted'

The Answer 2

68 people think this answer is useful

Convert timestamp to date in MYSQL

Make the table with an integer timestamp:

mysql> create table foo(id INT, mytimestamp INT(11));
Query OK, 0 rows affected (0.02 sec)

Insert some values

mysql> insert into foo values(1, 1381262848);
Query OK, 1 row affected (0.01 sec)

Take a look

mysql> select * from foo;
+------+-------------+
| id   | mytimestamp |
+------+-------------+
|    1 |  1381262848 |
+------+-------------+
1 row in set (0.00 sec)

Convert the number to a timestamp:

mysql> select id, from_unixtime(mytimestamp) from foo;
+------+----------------------------+
| id   | from_unixtime(mytimestamp) |
+------+----------------------------+
|    1 | 2013-10-08 16:07:28        |
+------+----------------------------+
1 row in set (0.00 sec)

Convert it into a readable format:

mysql> select id, from_unixtime(mytimestamp, '%Y %D %M %H:%i:%s') from foo;
+------+-------------------------------------------------+
| id   | from_unixtime(mytimestamp, '%Y %D %M %H:%i:%s') |
+------+-------------------------------------------------+
|    1 | 2013 8th October 04:07:28                       |
+------+-------------------------------------------------+
1 row in set (0.00 sec)

The Answer 3

66 people think this answer is useful

To just get a date you can cast it

cast(user.registration as date)

and to get a specific format use date_format

date_format(registration, '%Y-%m-%d')

SQLFiddle demo

The Answer 4

21 people think this answer is useful

If the registration field is indeed of type TIMESTAMP you should be able to just do:

$sql = "SELECT user.email, 
           info.name, 
           DATE(user.registration), 
           info.news
      FROM user, 
           info 
     WHERE user.id = info.id ";

and the registration should be showing as yyyy-mm-dd

The Answer 5

11 people think this answer is useful

Just use mysql’s DATE function:

mysql> select DATE(mytimestamp) from foo;

The Answer 6

7 people think this answer is useful

You should convert timestamp to date.

select FROM_UNIXTIME(user.registration, '%Y-%m-%d %H:%i:%s') AS 'date_formatted'

FROM_UNIXTIME

The Answer 7

4 people think this answer is useful

FROM_UNIXTIME(unix_timestamp, [format]) is all you need

FROM_UNIXTIME(user.registration, '%Y-%m-%d') AS 'date_formatted'

FROM_UNIXTIME gets a number value and transforms it to a DATE object,
or if given a format string, it returns it as a string.

The older solution was to get the initial date object and format it with a second function DATE_FORMAT… but this is no longer necessary

The Answer 8

3 people think this answer is useful

If you are getting the query in your output you need to show us the code that actually echos the result. Can you post the code that calls requeteSQL?

For example, if you have used single quotes in php, it will print the variable name, not the value

echo 'foo is $foo'; // foo is $foo

This sounds exactly like your problem and I am positive this is the cause.

Also, try removing the @ symbol to see if that helps by giving you more infromation.

so that

$SQL_result = @mysql_query($SQL_requete); // run the query

becomes

  $SQL_result = mysql_query($SQL_requete); // run the query

This will stop any error suppression if the query is throwing an error.

The Answer 9

2 people think this answer is useful

I did it with the ‘date’ function as described in here :

(SELECT count(*) as the-counts,(date(timestamp)) as the-timestamps FROM `user_data` WHERE 1 group BY the-timestamps)

The Answer 10

1 people think this answer is useful

Try:

SELECT strftime("%Y-%d-%m", col_name, 'unixepoch') AS col_name

It will format timestamp in milliseconds to yyyy-mm-dd string.

The Answer 11

1 people think this answer is useful

you can try this
The date is of timestamp type which has the following format: ‘YYYY-MM-DD HH:MM:SS’ or ‘2008-10-05 21:34:02.’

$res = mysql_query("SELECT date FROM times;");
while ( $row = mysql_fetch_array($res) ) {
   echo $row['date'] . "
";
}

The PHP strtotime function parses the MySQL timestamp into a Unix timestamp which can be utilized for further parsing or formatting in the PHP date function.

Here are some other sample date output formats that may be of practical use:

echo date("F j, Y g:i a", strtotime($row["date"]));                  // October 5, 2008 9:34 pm
echo date("m.d.y", strtotime($row["date"]));                         // 10.05.08
echo date("j, n, Y", strtotime($row["date"]));                       // 5, 10, 2008
echo date("Ymd", strtotime($row["date"]));                           // 20081005
echo date('\i\t \i\s \t\h\e jS \d\a\y.', strtotime($row["date"]));   // It is the 5th day.
echo date("D M j G:i:s T Y", strtotime($row["date"]));               // Sun Oct 5 21:34:02 PST 2008

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